jawab soal 4

$\Leftrightarrow sin(3x+10)\: =cos(x-20),\: 0\leq x\leq 90$

$\Leftrightarrow sin(3x+10)\: =sin(90-(x-20))$

$\Leftrightarrow sin(3x+10)\: =sin(110-x)$

$\Leftrightarrow 3x+10\: =110-x+n360\: \textrm{atau }3x+10\: =(180-(110-x))+n360$

$\Leftrightarrow 3x+10\: =110-x+n360\: \textrm{atau }3x+10\: =70+x+n360$

$*\Rightarrow 3x+10=110-x+n360$

$\Rightarrow 4x=100+n360$ $\Rightarrow x=25+n90$

$\Rightarrow x=25$

$*\Rightarrow 3x+10=70+x+n360$

$\Rightarrow x=30+n180$

$\Rightarrow x=30$

Hp ={25,30}

SOAL dan BAHAS

Pages

jawab soal 4