jawab soal 1

$2\: sin3x\: =\: \sqrt{3},\: 0\leq x\leq 180$
$sin3x\: =\: \frac{1}{2}\sqrt{3}$
$sin3x\: =sin60$

$3x\: =60+n360\: \textrm{atau}\:3x\: =(180-60)+n360$

$*\Leftrightarrow 3x\: =60+n360$

$\Leftrightarrow x\: =20+n120$

$\Leftrightarrow x\: =20,140$

$*\Leftrightarrow 3x\: =(180-60)+n360$
$\Leftrightarrow x\: =40+n120$

$\Leftrightarrow x\: =40,160$

Hp = {20, 40, 140, 160}

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jawab soal 1